There is a good article out from the colubian, advicating B-Roy for the All-NBA team, now being Blazer fans most of us will say "YES ABSOLUTELY!" but maybe today on the day after a wonderful win we can break down this and have a debate about it. First, for those who don't know there are 3 All-NBA "teams" they are voted on by writers and coaches from the NBA, and they vote based on position, Guards, Forwards, and Centers. So if Roy was to make it he would be considered one of the top 6 guards in the league.
So to decide if Roy belongs there, we just need a list of the top guards in the league, and here you go, in no specific order they are:
Wade, Kobe, Roy, Johnson, Parker, Paul, D. Williams, D. Harris, J. Terry, R. Allen, K. Martin, S. Nash, C. Billups, and Mo Williams. (If I forgot anyone just list them in your post)
To me when looking at the names the choices are pretty simple. Paul, Kobe, Wade, Parker, Williams, and Roy. All from the West, (except Wade) I know, maybe that is because I watch mostly western teams being a Blazer fan, but I just don't see any guards in the East that are better than these 6. Do you?
UPDATE: In his daily insider gems, Hollinger over at ESPN has this to say about the ALL NBA teams.
4. I've mentioned this before in chats, but we have an interesting dilemma brewing over All-NBA voting. The league's five best players, pretty much everyone would agree, have been LeBron James, Dwyane Wade, Kobe Bryant, Chris Paul and Dwight Howard.
However, the All-NBA voting is done by position, and there's only one forward in that quintet I mentioned above. Which means Tim Duncan is likely to butt out one of the guards, most likely Paul, unless the voters get creative and list Bryant as a forward.
The dilemma cascades a rung below, as well. If Paul is bumped to second team, that means Tony Parker and Brandon Roy would be duking it out for the other guard slot, while a pair of forwards who have had lesser seasons (Kevin Garnett and Dirk Nowitzki, I'm guessing) ease into second-team spots at those positions.